14.28: Sección 3.3 Respuestas
- Page ID
- 115206
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\ket}[1]{\left| #1 \right>}\)
\(\newcommand{\bra}[1]{\left< #1 \right|}\)
\(\newcommand{\braket}[2]{\left< #1 \vphantom{#2} \right| \left. #2 \vphantom{#1} \right>}\)
\(\newcommand{\braopket}[3]{\left< #1 \vphantom{#2}\vphantom{#3} \right| #2 \vphantom{#1}\vphantom{#3} \left| #3 \vphantom{#1}\vphantom{#2} \right>}\)
\(\newcommand{\qmvec}[1]{\mathbf{\vec{#1}}}\)
\(\newcommand{\op}[1]{\hat{\mathbf{#1}}}\)
\(\newcommand{\expect}[1]{\langle #1 \rangle}\)
\(\newcommand{\dfn}[1]{\emph{\textbf{#1}}}\)
1. \(y_{1}=1.550598190, \: y_{2} = 2.469649729\)
2. \(y_{1} = 1.221551366,\: y_{2} = 1.492920208\)
3. \(y_{1} = 1.890339767,\: y_{2} = 1.763094323\)
4. \(y_{1} = 2.961316248,\: y_{2} = 2.920128958\)
5. \(y_{1} = 2.475605264,\: y_{2} = 1.825992433\)
6.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | Exacto |
| \(1.0\) | \(54.654509699\) | \(54.648344019\) | \(54.647962328\) | \(54.647937102\) |
7.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | Exacto |
| \(2.0\) | \(1.353191745\) | \(1.353193606\) | \(1.353193712\) | \(1.353193719\) |
8.
| \(x\) | \(h=0.05\) | \(h=0.025\) | \(h=0.0125\) | Exacto |
| \(1.50\) | \(10.498658198\) | \(10.499906266\) | \(10.499993820\) | \(10.500000000\) |
9.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) |
| \(3.0\) | \(1.456023907\) | \(1.456023403\) | \(1.456023379\) | \(0.0000124\) | \(0.000000611\) | \(0.0000000333\) |
| Soluciones aproximadas | Residuales | |||||
10.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) |
| \(2.0\) | \(0.492663789\) | \(0.492663738\) | \(0.492663736\) | \(0.000000902\) | \(0.0000000508\) | \(0.00000000302\) |
| Soluciones aproximadas | Residuales | |||||
11.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(1.0\) | \(0.659957046\) | \(0.659957646\) | \(0.659957686\) | \(0.659957689\) |
12.
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(2.0\) | \(-0.750911103\) | \(-0.750912294\) | \(-0.750912367\) | \(-0.750912371\) |
13. Aplicando variación de parámetros al problema de valor inicial dado rinde\(y = ue^{−3x}\), donde\((A) u' = 1 − 4x + 3x^{2} − 4x^{3}, u(0) = −3\). Ya que\(u^{(5)} = 0\), el método Runge-Kutta produce la solución exacta de (A). Por lo tanto, el método semilineal de Euler produce la solución exacta del problema dado.


14.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(3.0\) | \(15.281660036\) | \(15.281981407\) | \(15.282003300\) | \(15.282004826\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(3.0\) | \(15.282005990\) | \(15.282004899\) | \(15.282004831\) | \(15.282004826\) |
15.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(2.0\) | \(0.904678156\) | \(0.904295772\) | \(0.904277759\) | \(0.904276722\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(2.0\) | \(0.904592215\) | \(0.904297062\) | \(0.904278004\) | \(0.904276722\) |
16.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(3.0\) | \(0.967523147\) | \(0.967523152\) | \(0.967523153\) | \(0.967523153\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(3.0\) | \(0.967523147\) | \(0.967523152\) | \(0.967523153\) | \(0.967523153\) |
17.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.0500\) | \(h=0.0250\) | \(h=0.0125\) | “Exacto” |
| \(1.50\) | \(0.343839158\) | \(0.343784814\) | \(0.343780796\) | \(0.343780513\) |

18.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(2.0\) | \(0.732633229\) | \(0.732638318\) | \(0.732638609\) | \(0.732638628\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.2\) | \(h=0.1\) | \(h=0.05\) | “Exacto” |
| \(2.0\) | \(0.732639212\) | \(0.732638663\) | \(0.732638630\) | \(0.732638628\) |
19.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.0500\) | \(h=0.0250\) | \(h=0.0125\) | “Exacto” |
| \(1.50\) | \(2.244025683\) | \(2.244024088\) | \(2.244023989\) | \(2.244023982\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.0500\) | \(h=0.0250\) | \(h=0.0125\) | “Exacto” |
| \(1.50\) | \(2.244025081\) | \(2.244024051\) | \(2.244023987\) | \(2.244023982\) |
20.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(1.0\) | \(0.056426886\) | \(0.056416137\) | \(0.056415552\) | \(0.056415515\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(1.0\) | \(0.056415185\) | \(0.056415495\) | \(0.056415514\) | \(0.056415515\) |
21.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(1.0\) | \(54.695901186\) | \(54.727111858\) | \(54.729426250\) | \(54.729594761\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(1.0\) | \(54.729099966\) | \(54.729561720\) | \(54.729592658\) | \(54.729594761\) |
22.
| Método Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(3.0\) | \(1.361384082\) | \(1.361383812\) | \(1.361383809\) | \(1.361383810\) |
| Método semilineal Runge-Kutta | ||||
| \(x\) | \(h=0.1\) | \(h=0.05\) | \(h=0.025\) | “Exacto” |
| \(3.0\) | \(1.361456502\) | \(1.361388196\) | \(1.361384079\) | \(1.361383810\) |
24.
| \(x\) | \(h=.1\) | \(h=.05\) | \(h=.025\) | Exacto |
| \(2.00\) | \(-1.000000000\) | \(-1.000000000\) | \(-1.000000000\) | \(-1.000000000\) |
25.
| \(x\) | \(h=.1\) | \(h=.05\) | \(h=.025\) | “Exacto” |
| \(1.00\) | \(1.000000000\) | \(1.000000000\) | \(1.000000000\) | \(1.000000000\) |
26.
| \(x\) | \(h=.1\) | \(h=.05\) | \(h=.025\) | “Exacto” |
| \(1.50\) | \(4.142171279\) | \(4.142170553\) | \(4.142170508\) | \(4.142170505\) |
27.
| \(x\) | \(h=.1\) | \(h=.05\) | \(h=.025\) | “Exacto” |
| \(3.0\) | \(16.666666988\) | \(16.666666687\) | \(16.666666668\) | \(16.666666667\) |


