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A.2: Poderes y logaritmos
https://espanol.libretexts.org/Matematicas/Calculo_vectorial_CLP-4_(Feldman_Rechnitzer_y_Yeager)/06%3A_Ap%C3%A9ndices/6.01%3A_Ap%C3%A9ndices/6.1.02%3A_Poderes_y_logaritmos
$\displaystyle e^{x+y}=e^xe^y, \quad e^{x-y}=\frac{e^x}{e^y}, \quad q^{x+y}=q^xq^y, \quad q^{x-y}=\frac{q^x}{q^y}$ \(\displaystyle \dfrac{d}{dx}e^x=e^x, \quad \dfrac{d}{dx}e^{g(x)}=g'(x)e^{g(x)}, \q... $\displaystyle e^{x+y}=e^xe^y, \quad e^{x-y}=\frac{e^x}{e^y}, \quad q^{x+y}=q^xq^y, \quad q^{x-y}=\frac{q^x}{q^y}$ $\displaystyle \dfrac{d}{dx}e^x=e^x, \quad \dfrac{d}{dx}e^{g(x)}=g'(x)e^{g(x)}, \quad \dfrac{d}{dx}q^x=(\ln q)\ q^x$ $\displaystyle \log_q x=\frac{\ln x}{\ln q}, \quad \ln x=\frac{\log_p x}{\log_p e}, \quad \log_q x=\frac{\log_p x}{\log_p q}$ $\displaystyle \ln\big(\frac{x}{y}\big)=\ln x-\ln y, \quad \log_q\big(\frac{x}{y}\big)=\log_q x-\log_q y$

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