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6.11: Soluciones
https://espanol.libretexts.org/Fisica/Astronomia_y_Cosmologia/Mec%C3%A1nica_Celestial_(Tatum)/06%3A_La_Esfera_Celestial/6.11%3A_Soluciones
$\tan α = \frac{\cos α_{22} \tan δ_{22} - \cos α_{12} \tan δ_{12} + a_1 \sin α_{12} - a_2 \sin α_{22}}{\sin α_{12} \tan δ_{12} - \sin α_{22} \tan δ_{22} + a_1 \cos α_{12} - a_2 \cos α_{22}},$ Entonc... $\tan α = \frac{\cos α_{22} \tan δ_{22} - \cos α_{12} \tan δ_{12} + a_1 \sin α_{12} - a_2 \sin α_{22}}{\sin α_{12} \tan δ_{12} - \sin α_{22} \tan δ_{22} + a_1 \cos α_{12} - a_2 \cos α_{22}},$ Entonces $\tan δ = \cos (α - α_{12}) \tan δ_{12} + \sin (α - α_{12} ) [\csc (α_{11} - α_{12}) \tan δ_{11} - \cot (α_{11} - α_{12}) \tan δ_{12}]$ o $\tan δ = \cos (α - α_{22}) \tan δ_{22} + \sin (α - α_{22} ) [\csc (α_{21} - α_{22}) \tan δ_{21} - \cot (α_{21} - α_{22}) \tan δ_{22}].$

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