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4.11: Solución Capitular (Practica+ Tareas)

  • Page ID
    151072
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    1.

    \ (\ PageIndex {6}\) “>
    \(x\)\(P(x)\)
    00.12
    10.18
    20.30
    30.15
    40.10
    50.10
    60.05
    Mesa\(\PageIndex{6}\)

    3.

    0.10 + 0.05 = 0.15

    5.

    1

    7.

    0.35 + 0.40 + 0.10 = 0.85

    9.

    1 (0.15) + 2 (0.35) + 3 (0.40) + 4 (0.10) = 0.15 + 0.70 + 1.20 + 0.40 = 2.45

    11.

    \ (\ PageIndex {7}\) “>
    \(x\)\(P(x)\)
    00.03
    10.04
    20.08
    30.85
    Mesa\(\PageIndex{7}\)

    13.

    Deje que\(X =\) el número de eventos Javier sea voluntario para cada mes.

    15.

    \ (\ PageIndex {8}\) “>
    \(x\)\(P(x)\)
    00.05
    10.05
    20.10
    30.20
    40.25
    50.35
    Mesa\(\PageIndex{8}\)

    17.

    1 — 0.05 = 0.95

    18.

    \(X =\)el número de carreras de negocios en la muestra.

    19.

    2, 3, 4, 5, 6, 7, 8, 9

    20.

    \(X =\)el número que responde “sí”

    22.

    0, 1, 2, 3, 4, 5, 6, 7, 8

    24.

    5.7

    26.

    0.4151

    28.

    \(X =\)el número de estudiantes de primer año seleccionados del estudio hasta que uno contestó “sí” que las parejas del mismo sexo deberían tener derecho al estado civil legal.

    30.

    1,2,...

    32.

    1.4

    35.

    0, 1, 2, 3, 4,...

    37.

    0.0485

    39.

    0.0214

    41.

    \(X =\)el número de adolescentes estadounidenses que mueren por lesiones en vehículos motorizados por día.

    43.

    0, 1, 2, 3, 4,...

    45.

    No

    48.

    1. 50.
      1. 53.

        \(X =\)el número de pacientes que llaman para afirmar tener la gripe, que en realidad tienen la gripe.

        55.

        0.0165

        57.

        1. 59.

          4. 4.43

          4

          63.

          • 65.
            1. 67.
              1. 69.
                1. 71.
                  1. 73.
                    1. Figura\(\PageIndex{4}\)
                    2. 75.
                      1. 77.
                        1. 79.

                          0, 1, 2 y 3

                          1. 82.
                            1. 84.

                              Deje que\(X =\) el número de bombillas defectuosas en una cuerda.

                              • Usando la distribución binomial:
                                • La aproximación de Poisson es muy buena, la diferencia entre las probabilidades es solo\(0.0026\).

                                  86.

                                  1. 88.
                                    1. 90.
                                      1. 92.
                                        1. 94.

                                          4


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