Buscar

Loading [MathJax]/jax/output/HTML-CSS/jax.js

6.5: Lineamientos generales para factorizar polinomios
https://espanol.libretexts.org/Matematicas/Algebra/Algebra_inicial/06%3A_Factoraje_y_resoluci%C3%B3n_por_factorizaci%C3%B3n/6.05%3A_Lineamientos_generales_para_factorizar_polinomios
$\begin{aligned} x^{3}+8y^{3}&=(x)^{3}+(2y)^{3}=(x+2y)(x^{2}-2xy+4y^{2}) \\ x^{3}-8y^{3} &= (x)^{3} -(2y)^{3} =(x-2y)(x^{2}+2xy+4y^{2}) \end{aligned}$ \(\begin{aligned} x^{6}-64y^{6}&=(x^{3}+8y^{3})... $\begin{aligned} x^{3}+8y^{3}&=(x)^{3}+(2y)^{3}=(x+2y)(x^{2}-2xy+4y^{2}) \\ x^{3}-8y^{3} &= (x)^{3} -(2y)^{3} =(x-2y)(x^{2}+2xy+4y^{2}) \end{aligned}$ $\begin{aligned} x^{6}-64y^{6}&=(x^{3}+8y^{3})(x^{3}-8y^{3}) \\ &=(x+2y)(x^{2}-2xy+4y^{2})(x-2y)(x^{2}+2xy+4y^{2}) \end{aligned}$ $\begin{aligned} a^{2}-b^{2} &=(a+b)(a-b) \\ x^{2}-(2x-1)^{2} &= [(x+(2x-1))][(x-(2x-1))] \\ &=(x+2x-1)(x-2x+1) \\ &=(3x-1)(-x+1) \end{aligned}$ 61. $(x^{8}+1)(x^{4}+1)(x^{2}+1)(x+1)(x−1)$

Search