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1.2.2E: Dominio y Rango
https://espanol.libretexts.org/Matematicas/Precalculo_y_Trigonometria/Libro%3A_Prec%C3%A1lculo_-_Una_investigaci%C3%B3n_de_funciones_(Lippman_y_Rasmussen)/01%3A_Funciones/1.02%3A_Dominio_y_Rango/1.2.2E%3A_Dominio_y_Rango
f\left(x\right)=\left\{ $\begin{array}{ccc} {5x} & {if} & {x<0} \\ {3} & {if} & {0\le x\le 3} \\ {x^{2} } & {if} & {x>3} \end{array}$ \right.\ \ \ \ \ \ \ \ \ \ \ \ \ \ 24. f\left(x\right)=\left\{\begin{a...f\left(x\right)=\left\{ $\begin{array}{ccc} {5x} & {if} & {x<0} \\ {3} & {if} & {0\le x\le 3} \\ {x^{2} } & {if} & {x>3} \end{array}$ \right.\ \ \ \ \ \ \ \ \ \ \ \ \ \ 24. f\left(x\right)=\left\{ $\begin{array}{ccc} {x^{3} +1} & {if} & {x<0} \\ {4} & {if} & {0\le x\le 3} \\ {3x+1} & {if} & {x>3} \end{array}$ \right.\) f\left(x\right)=\left\{ $\begin{array}{ccc} {3} & {if} & {x\le -2} \\ {-x+1} & {if} & {-2<x\le 1} \\ {3} & {if} & {x>1} \end{array}$ \right.\ \ \ \ \ \ \ \ 36.

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