x3y+2x2yz−6xz2=yz2−10 in terms of xxt+cos(θ)=x4t3−6t in terms of x Es posible resolver;x=5yy2−y+3log2(xy)=x+ez for x No es pos...x3y+2x2yz−6xz2=yz2−10 in terms of xxt+cos(θ)=x4t3−6t in terms of x Es posible resolver;x=5yy2−y+3log2(xy)=x+ez for x No es posible resolver para x; está dentro de un logaritmo y tiene un término lineal Es posible resolver;y=2x+ez−log2(x) or y=2x+ezx Es posible resolver;z=ln[log2(xy)−x]