\[\begin{gathered} (3+2 y) d y=2 \cos 2 x d x \\ \int_{-1}^{y}(3+2 y) d y=2 \int_{0}^{x} \cos 2 x d x \\ \left.\left.3 y+y^{2}\right]_{-1}^{y}=\sin 2 x\right]_{0}^{x} \\ y^{2}+3 y+2-\sin 2 x=0 \\ y_{\...(3+2y)dy=2cos2xdx∫y−1(3+2y)dy=2∫x0cos2xdx3y+y2]y−1=sin2x]x0y2+3y+2−sin2x=0y±=12[−3±√1+4sin2x]
