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17.2: Dos Péndulos Acoplados

  • Page ID
    130806
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    Tomaremos dos péndulos iguales, acoplados por un resorte ligero. Tomamos que la fuerza restauradora del resorte sea directamente proporcional a la diferencia angular entre los péndulos. (Esto resulta ser una buena aproximación.)

    Para pequeños ángulos de oscilación, tomamos el Lagrangiano para ser

    \ begin {ecuación}
    L=\ frac {1} {2} m\ ell^ {2}\ punto {\ theta} _ {1} ^ {2} +\ frac {1} {2} m\ ell^ {2}\ punto {\ theta} _ {2} ^ {2} -\ frac {1} {2} m g\ ell\ theta_ {1} ^ {2} -\ frac {1} {2} m g\ ell\ theta_ {2} ^ {2} -\ frac {1} {2} C\ izquierda (\ theta_ {1} -\ theta_ {2}\ derecha) ^ {2}
    \ end {ecuación}

    Denotando la frecuencia de péndulo único por\(\omega_{0}\), las ecuaciones de movimiento son (escribir\(\omega_{0}^{2}=g / \ell, k=C / m \ell^{2}\), entonces\(\left.[k]=T^{-2}\right)\)

    \ begin {ecuación}
    \ begin {array} {l}
    \ ddot {\ theta} _ {1} =-\ omega_ {0} ^ {2}\ theta_ {1} -k\ izquierda (\ theta_ {1} -\ theta_ {2}\ derecha)\
    \ ddot {\ theta} _ {2} =-\ omega_ {0} ^ {2}\ theta_ {2} -k\ izquierda (\ theta_ {2} -\ theta_ {1}\ derecha)
    \ end {array}
    \ end {ecuación}

    Buscamos una solución periódica, escribiendo

    \ begin {ecuación}
    \ theta_ {1} (t) =A_ {1} e^ {i\ omega t},\ quad\ theta_ {2} (t) =A_ {2} e^ {i\ omega t}
    \ end {ecuación}

    (Las soluciones finales del ángulo físico serán la parte real.)

    Las ecuaciones se convierten (en notación matricial):

    \ begin {ecuación}
    \ omega^ {2}\ left (\ begin {array} {c}
    A_ {1}\\
    A_ {2}
    \ end {array}\ right) =\ left (\ begin {array} {cc}
    \ omega_ {0} ^ {2} +k & -k\\
    -k &\ omega_ {0} ^ {2} +k
    \ end {array}\ derecha)\ izquierda (\ begin {array} {c}
    A_ {1}\\
    A_ {2}
    \ end {array}\ right)
    \ end {ecuación}

    Denotando el\(2 \times 2 \text { matrix by } \mathbf{M}\)

    \ begin {ecuación}
    \ mathbf {M}\ vec {A} =\ omega^ {2}\ vec {A},\ quad\ vec {A} =\ left (\ begin {array} {l}
    A_ {1}\\
    A_ {2}
    \ end {array}\ right)
    \ end {ecuación}

    Esta es una ecuación de vector propio, con\(\omega^{2}\) el valor propio, que se encuentra por el procedimiento estándar:

    \ begin {ecuación}
    \ operatorname {det}\ left (\ mathbf {M} -\ omega^ {2}\ mathbf {I}\ derecha) =\ izquierda|\ begin {array} {cc}
    \ omega_ {0} ^ {2} +k-\ omega^ {2} & -k\\
    -k &\ omega_ {0} ^ {2} +k-\ omega^ {2}
    \ end {array}\ derecha|=0
    \ end {ecuación}

    Resolviendo\(\omega^{2}=\omega_{0}^{2}+k \pm k\),, es decir

    \ begin {ecuación}
    \ omega^ {2} =\ omega_ {0} ^ {2},\ quad\ omega^ {2} =\ omega_ {0} ^ {2} +2 k
    \ final {ecuación}

    Los vectores propios correspondientes son (1,1) y (1, −1).


    This page titled 17.2: Dos Péndulos Acoplados is shared under a not declared license and was authored, remixed, and/or curated by Michael Fowler.