3.11: Examen de Aptitud
- Page ID
- 112481
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Examen de competencia
Simplifica las expresiones para los siguientes problemas.
\(-\{-[(-6)]\}\)
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\(-6\)
\(-|-15|\)
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\(-15\)
\(-[|-12|-10]^2\)
- Responder
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\(-4\)
\(-5(-6)+4(-8)-|-5|\)
- Responder
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\(-7\)
\(\dfrac{3(-8)-(-2)(-4-5)}{(-2)(-3)}\)
- Responder
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\(-7\)
\(-|7|-(2)^2+(-2)^2\)
- Responder
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\(-7\)
\(\dfrac{-6(2)(-2)}{-(-5-3)}\)
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\(3\)
\(\dfrac{-2\{[(-2-3)][-2]\}}{-3(4-2)}\)
- Responder
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\(5\)
Si\(z = \dfrac{x-u}{s}\),\(z\) es\(x = 14, u = 20\), y\(s = 2\).
- Responder
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\(-3\)
Al simplificar los términos para los siguientes problemas, escriba cada uno para que sólo aparezcan exponentes positivos.
\(\dfrac{1}{-(-5)^{-3}}\)
- Responder
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\(125\)
\(\dfrac{5x^3y^{-2}}{x^{-4}}\)
- Responder
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\(\dfrac{5x^3z^4}{y^2}\)
\(2^{-2}m^6(n-4)^{-3}\)
- Responder
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\(\dfrac{m^6}{4(n-4)^3}\)
\(4a^{-6}(2a^{-5})\)
- Responder
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\(\dfrac{8}{a^{11}}\)
\(\dfrac{6^{-1}x^3y^{-5}z^{-3}}{y^{-5}}\)
- Responder
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\(\dfrac{1}{6}\)
\(\dfrac{(k-6)^2(k-6)^{-4}}{(k-6)^3}\)
- Responder
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\(\dfrac{1}{(k-6)^5}\)
\(\dfrac{(y+1)^3(y-3)^4}{(y+1)^5(y-3)^{-8}}\)
- Responder
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\(\dfrac{(y-3)^{12}}{(y+1)^2}\)
\(\dfrac{(3^{-6})(3^2)(3^{-10})}{(3^{-5})(3^{-9})}\)
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\(1\)
\((a^4)^{-3}\)
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\(\dfrac{1}{a^{12}}\)
\([\dfrac{r^6s^{-2}}{m^{-5}n^4}]^{-4}\)
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\(\dfrac{n^{16}s^8}{m^{20}r^{24}}\)
\((c^0)^{-2}, c \not = 0\)
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\(1\)
Escribir 0.000271 usando notación científica.
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\(2.71 \times 10^{-4}\)
Escribir\(8.90 \times 10^5\) en forma estándar.
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890,000
Encuentra el valor de\((3 \times 10^5)(2 \times 10^{2})\).
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6000
Encuentra el valor de\((4 \times 10^{-16})^2\)
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\(1.6 \times 10^{-31}\)
Si\(k\) es un entero negativo, ¿es\(-k\) un entero positivo o negativo?
- Responder
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un entero positivo