18.11: Describir datos
- Page ID
- 110410
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- Diferentes mesas son posibles
\ (\ begin {array} {|l|l|}
\ hline\ text {Puntuación} &\ texto {Frecuencia}\\
\ hline 30 & 1\\
\ hline 40 & 0\\
\ hline 50 & 4\\
\ hline 60 & 3\\
\ hline 70 & 6\
\ hline 80 & 5\\ hline
\ hline 90 & 2\\
\ hline 100 & 3\\
\ hline
\ end {array}\)
- Esto es técnicamente un gráfico de barras, no un histograma:
3.
- \(5+3+4+2+1=15\)
- \(5 / 15=0.3333=33.33 \%\)
5. El bar está en\(25 \% .25 \%\) de\(20=5\) los estudiantes que obtuvieron un\(A\)
7.
- \((7.25+8.25+9.00+8.00+7.25+7.50+8.00+7.00) / 8=\$ 7.781\)
- En orden, 7.50 y 8.00 están en posiciones medias. Mediana\(=\$ 7.75\)
- \(0.25 * 8=2\)\(\mathrm{Q} 1\)es promedio de\(2^{\mathrm{nd}}\) y valores de\(3^{\mathrm{rd}}\) datos:\(\$ 7.375 \quad 0.75 * 8=6 . \mathrm{Q} 3\) es promedio de\(6^{\mathrm{th}}\) y valores de\(7^{\mathrm{th}}\) datos: resumen\(\$ 8.125\) de 5 números:\(\$ 7.00, \$ 7.375, \$ 7.75, \$ 8.125, \$ 9.00\)
- \(0.637\)
9.
- \((5 \times 0+3 \times 1+4 \times 2+2 \times 3+1 \times 5) / 15=1.4667\)
- La mediana es el 8 º valor de datos: 1 hijo
- \(0.25 \times 15=3.75 .\)Q1 es 4 valor de\(^{\text {th}}\) datos: 0 niños\(0.75 \times 15=11.25 .\) Q 3 es valor de\(12^{\text {th}}\) datos: 2 niños 5 -resumen del número: 0,0 1,2,5
11. Kendra gana $90,000. Kelsey gana 40,000 dólares. Kendra gana 50,000 dólares más.