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11.6: Resolver sistemas de ecuaciones no lineales
https://espanol.libretexts.org/Matematicas/Algebra/Algebra_Intermedia_(OpenStax)/11%3A_C%C3%B3nicas/11.06%3A_Resolver_sistemas_de_ecuaciones_no_lineales
\(\left\{\begin{array}{l}{x^{2}+y^{2}=9} \\ {x^{2}-y=9}\end{array}\right. \left\{\begin{array}{l}{9 x^{2}+y^{2}=9} \\ {y=3 x-3}\end{array}\right. \left\{\begin{array}{l}{x+y=4} \\ {y=x^{2}+2}\end{arra... $\left\{\begin{array}{l}{x^{2}+y^{2}=9} \\ {x^{2}-y=9}\end{array}\right. \left\{\begin{array}{l}{9 x^{2}+y^{2}=9} \\ {y=3 x-3}\end{array}\right. \left\{\begin{array}{l}{x+y=4} \\ {y=x^{2}+2}\end{array}\right.$ $\begin{array}{rl}{x^{2}+y^{2} = 7} &\quad { x^{2}+y^{2}=7} \\ {2^{2}+y^{2}=7} & \quad{(-2)^{2}+y^{2}=7} \\ {4+y^{2}=7} &\quad {4+y^{2}=7} \\ {y^{2}=3} &\quad {y^{2}=3} \\ {y=\pm \sqrt{3}} &\quad {y=\pm \sqrt{3}}\end{array}$
11.6: Resolver sistemas de ecuaciones no lineales
https://espanol.libretexts.org/Under_Construction/Matem%C3%A1ticas/%C3%81lgebra_Intermedia_(OpenStax)/11%3A_C%C3%B3nicos/11.06%3A_Resolver_sistemas_de_ecuaciones_no_lineales
\(\left\{\begin{array}{l}{x^{2}+y^{2}=9} \\ {x^{2}-y=9}\end{array}\right. \left\{\begin{array}{l}{9 x^{2}+y^{2}=9} \\ {y=3 x-3}\end{array}\right. \left\{\begin{array}{l}{x+y=4} \\ {y=x^{2}+2}\end{arra... $\left\{\begin{array}{l}{x^{2}+y^{2}=9} \\ {x^{2}-y=9}\end{array}\right. \left\{\begin{array}{l}{9 x^{2}+y^{2}=9} \\ {y=3 x-3}\end{array}\right. \left\{\begin{array}{l}{x+y=4} \\ {y=x^{2}+2}\end{array}\right.$ $\begin{array}{rl}{x^{2}+y^{2} = 7} &\quad { x^{2}+y^{2}=7} \\ {2^{2}+y^{2}=7} & \quad{(-2)^{2}+y^{2}=7} \\ {4+y^{2}=7} &\quad {4+y^{2}=7} \\ {y^{2}=3} &\quad {y^{2}=3} \\ {y=\pm \sqrt{3}} &\quad {y=\pm \sqrt{3}}\end{array}$

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