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    • https://espanol.libretexts.org/Matematicas/Algebra/Algebra_Intermedia_(OpenStax)/12%3A_Secuencias%2C_series_y_teorema_binomial/12.02%3A_Secuencias
      \(\begin{array} {}&{ 1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}} \\ {}&{n : 1,2,3,4,5} \\ {\text{We look for a pattern in the terms.}}&{\text { Terms: } 1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}...\(\begin{array} {}&{ 1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}} \\ {}&{n : 1,2,3,4,5} \\ {\text{We look for a pattern in the terms.}}&{\text { Terms: } 1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}} \\ {\text{The numerators are all one.}}&{\text { Pattern: } \frac{1}{1}, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \ldots \frac{1}{n}} \\ {\text{The denominators are the counting numbers from one to five.}}&{\text{The sum written in summation notation}} \\ {}&{1 + \frac{1}{…
    • https://espanol.libretexts.org/Under_Construction/Matem%C3%A1ticas/%C3%81lgebra_Intermedia_(OpenStax)/12%3A_Secuencias%2C_series_y_teorema_binomial/12.02%3A_Secuencias
      \(\begin{array} {}&{ 1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}} \\ {}&{n : 1,2,3,4,5} \\ {\text{We look for a pattern in the terms.}}&{\text { Terms: } 1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}...\(\begin{array} {}&{ 1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}} \\ {}&{n : 1,2,3,4,5} \\ {\text{We look for a pattern in the terms.}}&{\text { Terms: } 1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}} \\ {\text{The numerators are all one.}}&{\text { Pattern: } \frac{1}{1}, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \ldots \frac{1}{n}} \\ {\text{The denominators are the counting numbers from one to five.}}&{\text{The sum written in summation notation}} \\ {}&{1 + \frac{1}{…

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