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1.5.1: Ejercicios 1.5

  • Page ID
    113957
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    Términos y Conceptos

    Ejercicio\(\PageIndex{1}\)

    Explicar la relación entre funciones logarítmicas y funciones exponenciales.

    Responder

    Para la misma base, son inversos el uno del otro.

    Ejercicio\(\PageIndex{2}\)

    ¿Qué preguntas respondes cuando evalúas\(\log_5{(25)}\)?

    Responder

    \(25\) is \(5\) raised to what power?

    Ejercicio\(\PageIndex{3}\)

    ¿Cuál es el valor de la base para\(\ln{(x)}\)?

    Responder

    \(e\)

    Ejercicio\(\PageIndex{4}\)

    Explica por qué los logaritmos ayudan a resolver declaraciones exponenciales.

    Responder

    Los logaritmos ayudan a resolver declaraciones exponenciales porque logaritmos y exponenciales son funciones inversas.

    Problemas

    Evaluar la declaración dada en ejercicios\(\PageIndex{5}\)\(\PageIndex{8}\).

    Ejercicio\(\PageIndex{5}\)

    \(\displaystyle \log_3{(81)}\)

    Responder

    \(4\)

    Ejercicio\(\PageIndex{6}\)

    \(\displaystyle \ln{(e^{5.7})}\)

    Responder

    \(5.7\)

    Ejercicio\(\PageIndex{7}\)

    \(\displaystyle e^{-\ln{(x})}\)

    Responder

    \(\displaystyle \frac{1}{x}\)

    Ejercicio\(\PageIndex{8}\)

    \(\displaystyle 4^{\log_2{(2^2)}}\)

    Responder

    \(\displaystyle 16\)

    Escribir la declaración dada como un logaritmo sencillo simplificado en los ejercicios\(\PageIndex{9}\)\(\PageIndex{12}\).

    Ejercicio\(\PageIndex{9}\)

    \(\displaystyle 4 \log_3{(2x)}-\log_3{(y^2)}\)

    Responder

    \(\displaystyle \log_3{\Big( \frac{16x^4}{y^2}\Big)}\)

    Ejercicio\(\PageIndex{10}\)

    \(\displaystyle \frac{2}{3} \ln{(x)} + 3\ln{(2y)}\)

    Responder

    \(\displaystyle \ln{(8x^{2/3}y^3)}\)

    Ejercicio\(\PageIndex{11}\)

    \(\displaystyle (2x)\log_2{(3)}+ \log_2{(5)}\)

    Responder

    \(\displaystyle \log_2{(5 (3^{2x}))}\)

    Ejercicio\(\PageIndex{12}\)

    \(\displaystyle 3\ln{(xy)}-2\ln{(x^2y)}\)

    Responder

    \(\displaystyle \ln{\Big( \frac{y}{x} \Big)}\)

    En ejercicios\(\PageIndex{13}\)\(\PageIndex{17}\), resolver el problema dado para\(x\), si es posible. Si un problema no se puede resolver, explique por qué.

    Ejercicio\(\PageIndex{13}\)

    \(\displaystyle 5^x = 25\)

    Responder

    \(\displaystyle x=2\)

    Ejercicio\(\PageIndex{14}\)

    \(\displaystyle 5^x = -5\)

    Responder

    No es posible; no podemos elevar un número positivo a una potencia y obtener un número negativo.

    Ejercicio\(\PageIndex{15}\)

    \(\displaystyle 5^x = 0\)

    Responder

    No es posible; no podemos elevar un número positivo a una potencia y obtener un cero.

    Ejercicio\(\PageIndex{16}\)

    \(\displaystyle 5^x = 0.2\)

    Responder

    \(x=-1\)

    Ejercicio\(\PageIndex{17}\)

    \(\displaystyle 5^x = 1\)

    Responder

    \(x=0\)

    En ejercicios\(\PageIndex{18}\)\(\PageIndex{25}\), resolver el problema dado para\(x\).

    Ejercicio\(\PageIndex{18}\)

    \(\displaystyle 3^{x-6} =2\)

    Responder

    \(x=6+\log_3{(2)}\)

    Ejercicio\(\PageIndex{19}\)

    \(\displaystyle 4^{2x-5} = 3\)

    Responder

    \(\displaystyle x=\frac{5+\log_4{(3)}}{2}\)

    Ejercicio\(\PageIndex{20}\)

    \(\displaystyle 2^{5x+6} = 4\)

    Responder

    \(\displaystyle x=\frac{-4}{5}\)

    Ejercicio\(\PageIndex{21}\)

    \(\displaystyle 6^{x+\pi} = 2\)

    Responder

    \(\displaystyle x=\log_6{(2)} - \pi\)

    Ejercicio\(\PageIndex{22}\)

    \(\displaystyle \bigg( \frac{1}{6}\bigg)^{-3x-2}=36^{x+1}\)

    Responder

    \(\displaystyle x=0\)

    Ejercicio\(\PageIndex{23}\)

    \(\displaystyle -15=-8\ln{(3x)}+7\)

    Responder

    \(\displaystyle x=\frac{1}{3} e^{11/4}\)

    Ejercicio\(\PageIndex{24}\)

    \(\displaystyle 2^x=3^{x-1}\)

    Responder

    \(\displaystyle x=-\frac{\ln{(3)}}{\ln{(2)} -\ln{(3)}}\)

    Ejercicio\(\PageIndex{25}\)

    \(\displaystyle 8= 4\ln{(2x+5)}\)

    Responder

    \(\displaystyle x=\frac{e^2-5}{2}\)


    This page titled 1.5.1: Ejercicios 1.5 is shared under a CC BY-NC license and was authored, remixed, and/or curated by Amy Givler Chapman, Meagan Herald, Jessica Libertini.